Bonjour, A = (2/3)(3x+1)^2 B = (6x-3/2)(6/5x+4) C = (7/5x+4/3)^2
Mathématiques
Keynen
Question
Bonjour,
A = (2/3)(3x+1)^2
B = (6x-3/2)(6/5x+4)
C = (7/5x+4/3)^2
A = (2/3)(3x+1)^2
B = (6x-3/2)(6/5x+4)
C = (7/5x+4/3)^2
1 Réponse
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1. Réponse Solene15137
A = (2/3) (3x + 1)²
A = 2/3 × (3x² + 2 × 3x × 1 + 1²)
A = 2/3 × (3x² + 6x + 1)
A = 6/3x² + 12/3x + 2/3
A = 2x² + 4x + 2/3
B = (6x - 3/2) (6/5x + 4)
B = 36/5x + 24x - 18/10x + 12/2
B = 7,2x + 24x - 1,8x + 6
B = 35x + 6
C = (7/5x + 4/3)²
C = 7/5² + 2 × 7/5x × 4/3 + 4/3²
C = 49/25 + 46/15x + 16/9
C = 46/15x + 441/225 + 400/225
C = 46/15x + 841/225