Bonjour j’aurai besoin d’aide svp

1a) A = √98=√2*√49=7√2

B= √242=√2*√121=11√2

C =√245= √5*√49=7√5

D=√605=√5*√121=11√5

b)

E 3√2-2√98+√242/2=

3√2-14√2+(11√2)/2 =

(6√2-28√2+11√2)/2 =-11√2/2

F = 2√605-3√5+√245

F = 22√5-3√5+4√5=23√5

2) [1(√2+1)-1(√2-1)]/(√2+1)(√2-1)=

(√2+1-√2+1)/2-1=

2/-1=-2

H = [1(√5+2)-1(√5-2)]/(√5-2)(√5+2)=

(√5+2-√5+2)/5-4=4/1=4

F =